Small Engines (Lawn Mowers, etc.): John Deere S92 Sprocket, gear teeth, driven speed

Question
My neighbor gave an S92 riding mower to me. I got it started and working however i'd like to make it faster and learn some stuff on the way.

I decided to make the sprocket at the axle bigger.
But I don't know how to remove the axle.

I tried taking the casing to the chain off but i can't because one side is bolted to the transmission.( tecumseh peerless)

How do you remove axle, How do you remove the transmission?



I also sent you the same message on a different email,  scratch that one . My email is timpaperboy@juno.com      sorry


Answer
It's difficult for me to give you an exact account of how to disassemble something.  You will need to do a thorough visual inspection to determine the mounting locations for the transmission.

I question why you want this machine to go faster.  These machines are usually geared in such a way that they will travel faster than they need to anyway.  If you have determined that it isn't a belt slipping, etc. making it go slower than you think it should, the sprocket on the axle (driven) would need to be smaller.  Gear reduction is a function of the number of driven gear teeth divided by the number of drive gear teeth so making the driven smaller reduces the gear reduction (and torque) but increases the driven speed.  For example:  a ratio of 3.73:1 in a differential is accomplished by having 41 teeth on the driven (ring) gear and 11 on the drive (pinion) gear.  If you do the math, 41 divided by 11 is 3.73.  If you reduce the number of driven teeth to, say, 35 and do the math, the ratio is 3.18:1 so the speed of the driven would increase but the torque output would be lower.  

Hope this helps.